Grouped data: estimated mean, modal class and median class
When data is grouped you no longer know the exact values, so you estimate the mean using the middle of each group.
Estimating the mean
Multiply each midpoint by its frequency (fx), add them up, and divide by the total frequency.
| Time t (min) | Frequency f | Midpoint x | fx |
|---|---|---|---|
| 0 < t ≤ 10 | 5 | 5 | 25 |
| 10 < t ≤ 20 | 12 | 15 | 180 |
| 20 < t ≤ 30 | 18 | 25 | 450 |
| 30 < t ≤ 40 | 5 | 35 | 175 |
| Total | 40 | 830 |
Working it out
It is only an estimate because the real values in each class could be anywhere in the class.
Modal class and median class
The median is the (40 + 12) = 20.5th value. Cumulative frequencies: 5, 17, 35, 40.
So the median lies in the class 20 < t ≤ 30.
Estimate the mean time from the table in the lesson.
- Σfx = 830
- Σf = 40
- 830 ÷ 40 = 20.75
Answer: 20.75 minutes
Estimated mean = Σ(midpoint × frequency) ÷ Σfrequency. Modal class: highest frequency. Median class: where the (n + 1)/2th value falls.
- Mean
- The total of the values divided by the number of values.
- Median
- The middle value when the data are in order.
- Estimate
- An approximate answer, usually found by rounding each number to 1 significant figure.
All GCSE and International GCSE Mathematics key terms and definitions →
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2 more questions
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What is the midpoint of the class 10 < h ≤ 20?
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Answer: 15
(10 + 20) ÷ 2 = 15.
Times t (min): 0 < t ≤ 10, frequency 7; 10 < t ≤ 20, frequency 15; 20 < t ≤ 30, frequency 11; 30 < t ≤ 40, frequency 4. Which is the modal class?
- 0 < t ≤ 10
- 10 < t ≤ 20
- 30 < t ≤ 40
- 20 < t ≤ 30
Show the answer
Answer: 10 < t ≤ 20
The modal class has the highest frequency, 15.
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- Pearson Edexcel GCSE Mathematics (1MA1) specification, topic S4
- Pearson Edexcel International GCSE Mathematics (4MA1) specification, topic 6.2
Checked by the GCSE-ready editorial team, 17 October 2026. Last updated 2 October 2026. Spotted a mistake? Tell us and we will fix it.