Core practical: stretching a spring

Core practical 15.6 investigates how the extension of a spring depends on the force applied, and how much energy it stores.

Practise this lesson free (6 questions)

The method

1. Hang a spring from a clamp, with a metre rule clamped vertically beside it.
2. Fix a pointer to the bottom of the spring and record its position (the original length).
3. Add a 1 N weight, record the new position and work out the extension (new length − original length).
4. Add weights one at a time up to about 6 N. Read the ruler at eye level to avoid parallax error.
5. Plot force (y-axis) against extension (x-axis).
Safety: wear eye protection in case the spring snaps, and keep feet clear of falling weights.

Reading the graph

If the line is straight through the origin, extension is directly proportional to force: F = k × x.
The gradient of the line is the spring constant, k, in N/m.
Beyond the limit of proportionality, the line curves (a non-linear relationship). If stretched too far, the spring will not return to its original length (inelastic deformation).

Work done and energy stored

Stretching the spring does work, which is stored in its elastic potential energy store.
E = ½ × k × x2 (only up to the limit of proportionality).
This is the same as the area under the force-extension graph: E = ½ × F × x.
Worked example

A spring's length goes from 0.150 m to 0.190 m when a 2.0 N weight is hung on it. Find the spring constant and the energy stored.

  1. x = 0.190 − 0.150 = 0.040 m
  2. k = F ÷ x = 2.0 ÷ 0.040 = 50 N/m
  3. E = ½ × 50 × 0.0402 = 0.04 J

Answer: k = 50 N/m; energy stored = 0.04 J

Key idea

Measure the extension for each added weight with a pointer and ruler at eye level. A straight line through the origin shows F = kx; the gradient is k. Beyond the limit of proportionality the graph curves. Energy stored = ½kx2, the area under the graph.

Key words
Extension
The increase in length of a spring or wire when it is stretched.
Weight
The force of gravity on an object: W = m × g. Unit newton (N).
Limit of proportionality
The point beyond which extension is no longer proportional to the force.
Time
1 hour = 3600 s. Convert minutes and hours to seconds before using P = E ÷ t or Q = I × t.
Inelastic deformation
A change of shape that stays after the force is removed.

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Quick check

Try two quick questions

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Extra practice

2 more questions

Try each one, then tap to check.

  1. A spring is 10.0 cm long. With a weight on it, it is 13.2 cm long. What is the extension in metres?

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    Answer: 0.032 m

    13.2 − 10.0 = 3.2 cm = 0.032 m

  2. A force of 2.0 N gives an extension of 0.050 m. Calculate the spring constant.

    Show the answer

    Answer: 40 N/m

    k = F ÷ e = 2.0 ÷ 0.050 = 40 N/m

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Sources and references

Checked by the GCSE-ready editorial team, 17 October 2026. Last updated 2 October 2026. Spotted a mistake? Tell us and we will fix it.

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