Core practical: force, mass and acceleration
Core practical 2.19 investigates how the acceleration of a trolley depends on the force pulling it and on its mass. Light gates make the timing accurate.
Measuring speed with light gates
speed = length of card ÷ time the beam is blocked
With two light gates (or a double card), you get two speeds and the time between them, so:
a = (v − u) ÷ t
Light gates remove human reaction time from the timing, so they are more accurate than a stopwatch.
The method
2. The weight of the hanging mass is the accelerating force.
3. Changing the force: move masses one at a time from the trolley to the hanger. This keeps the total mass being accelerated the same.
4. Changing the mass: add masses to the trolley but keep the hanging mass the same.
5. Record the acceleration each time and repeat to find means.
What the results show
For a fixed mass, acceleration is directly proportional to the force: a graph of a against F is a straight line through the origin.
For a fixed force, acceleration decreases as the mass increases.
Safety: put something soft at the end of the runway to catch the trolley, and keep feet clear of falling masses.
A 0.10 m card blocks a light gate for 0.050 s. A second gate further on is blocked for 0.025 s, 0.50 s later. Find the acceleration.
- u = 0.10 ÷ 0.050 = 2.0 m/s
- v = 0.10 ÷ 0.025 = 4.0 m/s
- a = (4.0 − 2.0) ÷ 0.50 = 4.0 m/s2
Answer: 4.0 m/s2
Speed = card length ÷ time the beam is blocked; a = (v − u) ÷ t. Move masses from trolley to hanger to change force without changing total mass. Acceleration is proportional to force and decreases with mass: F = ma.
- Acceleration
- The rate of change of velocity: change in velocity ÷ time. Unit m/s^{2}.
- Time
- 1 hour = 3600 s. Convert minutes and hours to seconds before using P = E ÷ t or Q = I × t.
- Friction
- A force that opposes motion between surfaces in contact.
- Weight
- The force of gravity on an object: W = m × g. Unit newton (N).
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2 more questions
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A 0.10 m card blocks a light gate for 0.04 s. What is the speed of the trolley?
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Answer: 2.5 m/s
speed = card length ÷ time = 0.10 ÷ 0.04 = 2.5 m/s
A trolley's speed rises from 0.2 m/s to 1.4 m/s in 0.6 s. What is its acceleration?
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Answer: 2 m/s2
a = (1.4 − 0.2) ÷ 0.6 = 1.2 ÷ 0.6 = 2 m/s2
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- Pearson Edexcel GCSE Physics (1PH0) specification, topic 2.11, 2.15, 2.19
- Pearson Edexcel International GCSE Physics (4PH1) specification, topic 1.5, 1.17
- Pearson Edexcel GCSE (9-1) Physics (1PH0) specification
Checked by the GCSE-ready editorial team, 17 October 2026. Last updated 2 October 2026. Spotted a mistake? Tell us and we will fix it.
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