Core practical: densities of solids and liquids

Core practical 14.3 measures the mass and volume of solids and liquids so you can calculate their densities with ρ = m ÷ V.

Practise this lesson free (6 questions)

Solids: regular and irregular

1. Zero the balance, then measure the mass of the object.
2. Regular solid (such as a cuboid): measure its length, width and height with a ruler (or vernier calipers for small objects). Volume = length × width × height.
3. Irregular solid (such as a stone): fill a displacement (eureka) can with water until it runs out of the spout, and wait for the dripping to stop. Put an empty measuring cylinder under the spout. Lower the object in gently on a thread. The volume of water that flows out equals the volume of the object.
4. Another way: put water in a measuring cylinder, read the level, add the object and read the level again. The rise in level is the object's volume.
5. Calculate density = mass ÷ volume.

Liquids

1. Put an empty measuring cylinder on the balance and zero it (or record the mass of the empty cylinder).
2. Pour in some of the liquid, for example 50 cm3, and read the volume.
3. Record the mass. This is the mass of the liquid only (if you recorded the empty mass, subtract it).
4. Calculate density = mass ÷ volume. Using a larger volume of liquid makes the percentage uncertainty in your readings smaller.
Read the volume at eye level from the bottom of the meniscus to avoid parallax error.
Safety: wipe up spills, keep water away from the balance and other electrical equipment, and lower heavy objects gently so the glassware does not crack.

Units and results

ρ = m ÷ V. With mass in g and volume in cm3, density is in g/cm3. With kg and m3, it is in kg/m3.
1 g/cm3 = 1000 kg/m3, and 1 cm3 = 1 ml.
Water has a density of about 1 g/cm3 (1000 kg/m3). Objects less dense than water float in it.
Repeat each measurement and calculate a mean. Errors to watch for: water splashing out of the displacement can, air bubbles stuck to the object, and liquid left behind when pouring.
Worked example

A stone has a mass of 156 g. In a measuring cylinder, the water level rises from 40 cm3 to 100 cm3 when the stone is added. Find its density in g/cm3 and in kg/m3.

  1. V = 100 − 40 = 60 cm3
  2. ρ = m ÷ V = 156 ÷ 60 = 2.6 g/cm3
  3. 2.6 × 1000 = 2600 kg/m3

Answer: 2.6 g/cm3 = 2600 kg/m3

Key idea

Measure mass with a zeroed balance. Find volume from length × width × height (regular solid), by displacement (irregular solid) or from a measuring cylinder read at eye level (liquid). Then ρ = m ÷ V. 1 g/cm3 = 1000 kg/m3.

Key words
Displacement
Distance moved in a stated direction. A vector.
Density
Mass per unit volume: ρ = m ÷ V. Unit kg/m^{3}.

All GCSE and International GCSE Physics key terms and definitions →

Quick check

Try two quick questions

See if it has sunk in. Answers are marked straight away.

Extra practice

2 more questions

Try each one, then tap to check.

  1. A rectangular block measures 3.0 cm by 2.0 cm by 2.0 cm and has a mass of 96 g. Calculate its density in g/cm3.

    Show the answer

    Answer: 8 g/cm3

    V = 3.0 × 2.0 × 2.0 = 12 cm3. ρ = 96 ÷ 12 = 8 g/cm3.

  2. A stone has a mass of 81 g. When it is lowered into a measuring cylinder, the water level rises from 30 cm3 to 60 cm3. Calculate the density of the stone in g/cm3.

    Show the answer

    Answer: 2.7 g/cm3

    V = 60 − 30 = 30 cm3. ρ = 81 ÷ 30 = 2.7 g/cm3.

Check you have got it

Answer 6 quick questions with instant marking. If you get one wrong, GCSE-ready shows you why and gives you another go. It is free, and you do not need an account.

Video for this lesson coming soon. Subscribe on YouTube

Sources and references

Checked by the GCSE-ready editorial team, 27 October 2026. Last updated 2 October 2026. Spotted a mistake? Tell us and we will fix it.

What do exam command words like explain and evaluate mean? →

Related lessons