Core practical: densities of solids and liquids
Core practical 14.3 measures the mass and volume of solids and liquids so you can calculate their densities with ρ = m ÷ V.
Solids: regular and irregular
2. Regular solid (such as a cuboid): measure its length, width and height with a ruler (or vernier calipers for small objects). Volume = length × width × height.
3. Irregular solid (such as a stone): fill a displacement (eureka) can with water until it runs out of the spout, and wait for the dripping to stop. Put an empty measuring cylinder under the spout. Lower the object in gently on a thread. The volume of water that flows out equals the volume of the object.
4. Another way: put water in a measuring cylinder, read the level, add the object and read the level again. The rise in level is the object's volume.
5. Calculate density = mass ÷ volume.
Liquids
2. Pour in some of the liquid, for example 50 cm3, and read the volume.
3. Record the mass. This is the mass of the liquid only (if you recorded the empty mass, subtract it).
4. Calculate density = mass ÷ volume. Using a larger volume of liquid makes the percentage uncertainty in your readings smaller.
Read the volume at eye level from the bottom of the meniscus to avoid parallax error.
Safety: wipe up spills, keep water away from the balance and other electrical equipment, and lower heavy objects gently so the glassware does not crack.
Units and results
1 g/cm3 = 1000 kg/m3, and 1 cm3 = 1 ml.
Water has a density of about 1 g/cm3 (1000 kg/m3). Objects less dense than water float in it.
Repeat each measurement and calculate a mean. Errors to watch for: water splashing out of the displacement can, air bubbles stuck to the object, and liquid left behind when pouring.
A stone has a mass of 156 g. In a measuring cylinder, the water level rises from 40 cm3 to 100 cm3 when the stone is added. Find its density in g/cm3 and in kg/m3.
- V = 100 − 40 = 60 cm3
- ρ = m ÷ V = 156 ÷ 60 = 2.6 g/cm3
- 2.6 × 1000 = 2600 kg/m3
Answer: 2.6 g/cm3 = 2600 kg/m3
Measure mass with a zeroed balance. Find volume from length × width × height (regular solid), by displacement (irregular solid) or from a measuring cylinder read at eye level (liquid). Then ρ = m ÷ V. 1 g/cm3 = 1000 kg/m3.
- Displacement
- Distance moved in a stated direction. A vector.
- Density
- Mass per unit volume: ρ = m ÷ V. Unit kg/m^{3}.
All GCSE and International GCSE Physics key terms and definitions →
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A rectangular block measures 3.0 cm by 2.0 cm by 2.0 cm and has a mass of 96 g. Calculate its density in g/cm3.
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Answer: 8 g/cm3
V = 3.0 × 2.0 × 2.0 = 12 cm3. ρ = 96 ÷ 12 = 8 g/cm3.
A stone has a mass of 81 g. When it is lowered into a measuring cylinder, the water level rises from 30 cm3 to 60 cm3. Calculate the density of the stone in g/cm3.
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Answer: 2.7 g/cm3
V = 60 − 30 = 30 cm3. ρ = 81 ÷ 30 = 2.7 g/cm3.
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- Pearson Edexcel GCSE Physics (1PH0) specification, topic 14.2, 14.3
- Pearson Edexcel International GCSE Physics (4PH1) specification, topic 5.3, 5.4
- Topic 14 Particle model statements, Edexcel GCSE Physics 1PH0 (Tutordex)
- Edexcel International GCSE Physics 4PH1 statements 5.3 and 5.4 (Tutordex)
- Physics & Maths Tutor, Edexcel GCSE Physics CP 6: Density
- Required practical: density, eureka can method (LessonUp)
Checked by the GCSE-ready editorial team, 27 October 2026. Last updated 2 October 2026. Spotted a mistake? Tell us and we will fix it.
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