Forming and solving quadratic equations

Areas, Pythagoras and falling objects often lead to quadratic equations. Form the equation, solve it, then decide which solutions make sense.

Practise this lesson free (6 questions)

Forming the quadratic

Write the fact as an equation, expand, then rearrange so one side is 0.
A rectangle is x cm wide and (x + 4) cm long with area 45 cm2:
x(x + 4) = 45, so x2 + 4x − 45 = 0.

Solve and reject

x2 + 4x − 45 = (x + 9)(x − 5) = 0, so x = −9 or x = 5.
A width cannot be negative, so reject x = −9. The width is 5 cm.
If it does not factorise, use the quadratic formula.

Pythagoras with x

A right-angled triangle has sides x, x + 7 and hypotenuse x + 8.
x2 + (x + 7)2 = (x + 8)2
x2 + x2 + 14x + 49 = x2 + 16x + 64
x2 − 2x − 15 = 0, so (x − 5)(x + 3) = 0 and x = 5.
Worked example

A rectangle is x cm wide and (x + 3) cm long. Its area is 70 cm2. Find x.

  1. x(x + 3) = 70
  2. x2 + 3x − 70 = 0
  3. (x + 10)(x − 7) = 0
  4. x = −10 (reject) or x = 7

Answer: x = 7

Key idea

Form the equation, rearrange to = 0, solve by factorising or the formula, then reject any answer that is impossible in context.

Key words
Quadratic
An expression or equation where the highest power of x is 2, such as x^{2} − 5x + 6.
Equation
A statement with an equals sign that is true for particular values of the letter, such as 3x + 1 = 10.
Formula
A rule linking two or more variables, such as A = πr^{2}.
Factorise
Write an expression as a product by taking out common factors or putting it into brackets.
Hypotenuse
The longest side of a right-angled triangle, opposite the right angle.

All GCSE and International GCSE Mathematics key terms and definitions →

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Extra practice

2 more questions

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  1. A rectangle is x cm wide and (x + 7) cm long. Its area is 60 cm2. Find x.

    Show the answer

    Answer: 5 cm

    x2 + 7x − 60 = 0 gives x = 5 (x = −12 is rejected).

  2. A right-angled triangle has shorter sides x cm and (x + 2) cm and hypotenuse (x + 4) cm. Find x.

    Show the answer

    Answer: 6 cm

    x2 + (x + 2)2 = (x + 4)2 simplifies to x2 − 4x − 12 = 0, so x = 6.

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Sources and references

Checked by the GCSE-ready editorial team, 17 October 2026. Last updated 2 October 2026. Spotted a mistake? Tell us and we will fix it.

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