Calculus: turning points, maxima, minima and motion
International GCSE Higher uses differentiation to find turning points, to solve 'largest' and 'smallest' problems, and to describe motion.
Turning points
y = x3 โ 12x: dydx = 3x2 โ 12 = 0, so x2 = 4 and x = โ2 or 2.
y-values: x = โ2 gives y = 16; x = 2 gives y = โ16.
Maximum or minimum?
You can also check the gradient either side: + then โ is a maximum; โ then + is a minimum.
For y = x3 โ 12x: (โ2, 16) is a maximum and (2, โ16) a minimum.
Motion and practical problems
s = t3 โ 4t2 + 5t: v = 3t2 โ 8t + 5 and a = 6t โ 8.
For a practical problem, write the quantity in one variable, differentiate and set equal to 0.
A = x(40 โ 2x): dAdx = 40 โ 4x = 0, so x = 10 and A = 200.
s = t3 โ 4t2 + 5t. Find the velocity when t = 2.
- v = dsdt = 3t2 โ 8t + 5
- t = 2: 12 โ 16 + 5 = 1
Answer: v = 1
Solve dy/dx = 0 for turning points; decide maximum or minimum from the shape or the gradient either side. Velocity = ds/dt and acceleration = dv/dt.
- Gradient
- The steepness of a line: change in y รท change in x. It is m in y = mx + c.
- Turning point
- The point where a curve changes from going down to going up or the other way: a minimum or maximum.
All GCSE and International GCSE Mathematics key terms and definitions โ
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2 more questions
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Find the y-coordinate of the maximum point of y = x3 โ 27x.
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Answer: 54
3x2 โ 27 = 0 gives x = ยฑ3. The maximum is at x = โ3: (โ3)3 โ 27(โ3) = โ27 + 81 = 54.
y = x3 โ 12x. What kind of turning point is at x = โ2?
- It is not a turning point
- Neither
- A minimum
- A maximum
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Answer: A maximum
dydx = 3x2 โ 12 = 0 at x = โ2. d2ydx2 = 6x = โ12, negative, so a maximum.
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Checked by the GCSE-ready editorial team, 17 October 2026. Last updated 2 October 2026. Spotted a mistake? Tell us and we will fix it.