Core practical: pH and enzyme activity

Core practical 1.10 investigates how pH affects the enzyme amylase. You also need to calculate rates and know how enzymes build up and break down big molecules.

Practise this lesson free (6 questions)

Factors that affect enzyme activity

Temperature: rate rises up to the optimum, then falls quickly as the enzyme is denatured.
pH: each enzyme has an optimum pH. Away from it, the active site changes shape.
Substrate concentration: the rate rises as more substrate is added, then levels off when all the active sites are busy at the same time.

The method

1. Put one drop of iodine solution into each dip of a spotting tile.
2. Put amylase solution and a buffer solution (to fix the pH) in a test tube in a water bath at a set temperature, for example 35 °C.
3. Add starch solution, mix and start the stopwatch.
4. Every 10 seconds, put a drop of the mixture into the next dip of iodine.
5. When the iodine stays orange-brown, all the starch has been broken down. Record the time.
6. Repeat with buffers of different pH. Keep the temperature, volumes and concentrations the same.

Rates and enzymes in synthesis

rate = 1 ÷ time (for example, starch gone in 50 s gives 1 ÷ 50 = 0.02 s-1). If an amount is measured: rate = amount of product ÷ time.
Enzymes break down large molecules: carbohydrates into sugars, proteins into amino acids, lipids into fatty acids and glycerol.
Enzymes also synthesise (build) large molecules: sugars into starch, glycogen and cellulose; amino acids into proteins; fatty acids and glycerol into lipids.
Worked example

At pH 6 the starch was all broken down after 40 s. At pH 8 it took 160 s. Calculate the rate at each pH and say which pH is nearer the optimum.

  1. Rate = 1 ÷ time
  2. pH 6: 1 ÷ 40 = 0.025 s-1
  3. pH 8: 1 ÷ 160 = 0.00625 s-1
  4. The higher rate is at pH 6.

Answer: pH 6 (0.025 s-1) is nearer the optimum than pH 8 (0.00625 s-1).

Key idea

Use iodine to test for starch every 10 s; when it stays orange-brown the starch has gone. Buffers fix the pH, the water bath fixes the temperature. Rate = 1 ÷ time. Enzymes both break down and build up large molecules.

Key words
Enzyme
A protein that acts as a biological catalyst.
Denatured
When an enzyme's active site changes shape permanently, for example because of high temperature or the wrong pH, so the substrate no longer fits.
Active site
The part of an enzyme where the substrate fits and the reaction happens. Its shape is specific to one substrate.
Glycogen
The storage carbohydrate in animals and fungi, made from many glucose molecules.

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Common mistakes
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Extra practice

2 more questions

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  1. The starch was all broken down after 50 s. Calculate the rate as 1 ÷ time, in s-1.

    Show the answer

    Answer: 0.02 s-1

    1 ÷ 50 = 0.02 s-1

  2. An enzyme makes 90 cm3 of oxygen in 5 minutes. Calculate the mean rate in cm3 per second.

    Show the answer

    Answer: 0.3 cm3/s

    5 minutes = 300 s. 90 ÷ 300 = 0.3 cm3/s

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Sources and references

Checked by the GCSE-ready editorial team, 17 October 2026. Last updated 2 October 2026. Spotted a mistake? Tell us and we will fix it.

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